√99以上 x^2 y^2-2y=0 graph 261762-Graph the circle x^2+y^2+4x-2y-20=0

The graphs of the equations 2x 3y – 2 = 0 and x – 2y – 8 = 0 are two lines which are (a) coincident (b) parallel asked in Mathematics by Mubarak ( 326k points) linear equations in two variables

Graph the circle x^2+y^2+4x-2y-20=0-Note General Form always has x 2 y 2 for the first two terms Going From General Form to Standard Form Now imagine we have an equation in General Form x 2 y 2 Ax By C = 0 How can we get it into Standard Form like this?Find the equation of the parabola y = ax2 bx c that passes through the points To verify your result, use a graphing utility to plot the points and graph the parabola (−2, −15), (−1, −4), (1/2,10) y=?

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 it is a circle with radius r = 2 and center at (h,k) = ( −1,0) Explanation From the given equation x2 y2 2x −3 = 0 perform completing the square method to determine if its a circle, ellipse, hyperbola There are 2 second degree terms so we are sure it is not parabola x2 y2 2x −3 = 0 x2 2x y2 = 3 add 1 to both sides of the equationThat's a circle Compare with the general equation of a circle and write down the values of the constants , and The centre of the circle is The radius of the circle is If you don't like memorising formulae, do it like this It'll take only a few seconds extra Start by completing the square

Incoming Term: x^2+y^2-2y=0 graph, x^2+y^2-4x+2y-11=0 graph, (x^2+y^2-1)^3-x^2y^3=0 graph, graph the circle x^2+y^2+4x-2y-20=0, graph the circle x^2+y^2-14x+2y+41=0,
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